DNA Replication: Simple Steps of DNA replication in E.Coli
DNA replication steps start at unique chromosomal origins, processed bidirectionally, and is semi-conservative. DNA replication mechanisms depend on prior events: identification of a system capable of sustaining in-vitro replication of small plasmids carrying “Ori.C”
DNA replication is the process by which a double-stranded DNA molecule is copied to produce two identical DNA molecules. Replication is an essential process because, whenever a cell divides, the two new daughter cells must contain the same genetic information, or DNA, like the parent cell.
Table of Contents
Basic Steps of DNA Replication
The synthesis of a DNA molecule (or) DNA Replication process can be divided into THREE stages:
Initiation
Elongation
Termination
1. Initiation Stage
The E.Coli DNA replication process, called “Ori.C”, consists of 245 base pairs, many of which are highly conserved among bacteria.
The key sequences for this discussion are two series of short repeats; there repeats of a 13 base pair sequence and four repeats of a 9 base pair sequence.
At least “Eight different enzymes” (or) “Proteins” participate in the initiation phase of replication. They open the DNA helix at the origin and establish a preparing complex that sets the stage for subsequent reactions.
The key component in the initiation process is the Dna.A protein. A complex of about twenty Dna.A protein molecule binds to the four Nine base pairs repeats in the origin.
In a reaction that requires ATP and is facilitated by the bacterial histone-like protein “HU”, the Dna.A protein recognizes and successfully denatures the DNA in the region of the there 13 base pairs repeats, which are rich in A=T pair.
The Dna.B protein then binds to this region in a reaction that requires the Dna.C protein. Dna.B is a “Helicase” that unwinds duplex DNA. The helicases constitute a class of enzymes that can move along a DNA duplex utilizing a class of enzymes that can move along a DNA duplex utilizing the energy of ATP hydrolysis to separate the strands.
The separated strands are inhibited from subsequently re-annealing by the E.Coli Single-Stranded binding protein (SSBP), which binds to both separated strands. Multiple molecules of SSB bind cooperatively to single-stranded DNA, stabilizing the separated DNA strands and preventing renaturation.
DNA replication must occur only once in each cell cycle. Initiation is the only phase of replication that is regulated, but the mechanism is not yet well understood.
The Dna.A protein hydrolyzes its tightly bound ATP slowly (about 1 hour) to form an inactive Dna.A–ADP complex. Reactivating this complex is facilitated by an interaction between Dna.A protein and acidic phospholipids in the bacterial plasma membrane.
Initiation at inappropriate times is prevented by the presence of the inactive Dna.A-ADP complex by the binding of a protein called “ICI” (Inhibitor of chromosomal initiation) to the 13 base pair repeats, and perhaps by other factors.
2. Elongation Stage
The elongation phase of replication consists of two seemingly similar operations that are mechanically quite distinct: Leading strand synthesis and Lagging synthesis. Several enzymes at the replication fork are important to the synthesis of both strands. “DNA helicases” unwind the parental DNA.“DNA topoisomerases” relieve the tropological stress included by the “Helicases”, and “SSBP” stabilizes the separated strands.
a) DNA Replication leading strand synthesis
It begins with the synthesis by “Primase” of a short (10 to 60 nucleotide) RNA primer at the replication origin.
Deoxyribonucleotides are then added to this primer by DNA polymerase-III once was begun, leading strand synthesis proceeds continuously, keeping pace with the replication fork.
b) DNA Replication Lagging strand synthesis
It must be accomplished in short fragments (Okazaki fragments) synthesized in the direction opposite to the fork movement.
Each fragment must have its own RNA primer synthesized by “primase”, and positioning of the primers must be controlled and coordinated with fork movement.
The regulatory apparatus for “lagging strand synthesis” is a traveling protein machine called a “ PRIMOSOME”, which consists of several different proteins including the Dna.B protein, Dna.C protein, and Primase.
The primosome moves along the lagging strand template in the 5’à3’ direction, keeping pace with the replication fork.
As it moves the primosome at intervals compels primase to synthesize short (10 to 60) residues. RNA primer to which DNA is then added by DNA polymerase-III.
The direction of the synthetic reactions of “Primase” and “Polymerase-III” is opposite to the direction of the primosome movement.
When the new Okazaki fragment is complete, the RNA primer is removed by DNA polymerase-I and is replaced with DNA by the same enzyme. The remaining nick is sealed by “DNA ligase”.
3. Termination Stage
a) Termination of Replication of a circle
There are two possible modes of replication:
There are defined termination sequences, or
Two growing points collide and termination occurs whenever the collision point happens to be.
In both cases, termination might occur exactly halfway around the circle. Both termination modes have been observed.
Termination has a “Topological problem”. When double-stranded circular DNA replicates semi conservatively, the result is a pair of circles that are linked as in a chain.
Such a structure is called “CATENANE”. Catenated molecules have been observed in numerous systems, and evidence is accumulating to indicate that they result from replication.
“DNA Gyrase” is capable of de-catenating two circles, which enzyme is responsible for the separation of daughter molecules.E.coli chromosome and several plasmids carry specific sequences, called “ter sites”, where TBP ( ter binding protein) or ‘Tus protein’ bind.
In the termination zone of E.coli, there are three ter sites (ter A, ter D and terE) for a counter-clockwise fork. These six sites are arranged in an overlapping manner, laving no “Replication – free” gap on the chromosome. TBP-ter complexes formed at “ter” sites stall the replication fork, by inhibiting the DNA helicase or DnaB.
When this termination zone is deleted, replication stops, simply by the meeting of opposite replication forks, suggesting that the termination zone is not essential.
b) Termination in ‘Linear’ DNA molecules:
E.Coli phage T7 DNA replicates as a linear molecule. The origin is located 17% of the total distance from the left end of the molecule and replication is bidirectional. Initially, there is a single replication bubble (molecule-I), and when the leftward fork reaches the terminus, the molecules assume a “Y”-form (molecule-III).
“Ribonucleases” exist that can remove this RNA but once it has been removed, either a 5’-OH group would remain at the ends of the molecule.
Interaction of “Tus protein” with termination sites stops DNA replication:
Although much research attention has been focused on replication origins, E.Coli DNA also has been shown to contain termination (TER) sites, which bind a specific protein called Tus.
This protein may act to stop replication by preventing “Helicase (DnaB) from unwinding duplex DNA, thereby interrupting the function of the growing fork.
The details of the mechanism that arrests the growing fork are not yet clear. Replication of the circular E.coli chromosome produces two interlocking daughter chromosomes, which must be separated.
DNA Replication Video
MCQ on DNA Replication (Check your Basics)
DNA Replication
This MCQ was prepared from "DNA Replication " chapter (Unit 4). Here the question collected from analysis, general and from old papers. Try to solve the given question
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Question 1
Ciprofloxacin is a synthetic chemotherapeutic antibiotic of the Flouroquinolone drug class. The target of antibiotic Ciprofloxacin is...
A
Replication
B
Protein Synthesis
C
Cell wall synthesis
D
Membrane Structure
Question 2
Among the following which is termed as proof reading activity of DNA polymerase?
A
5->3' Polymerase activity
B
5->3' Exonuclease activity
C
3->5' Polymerase activity
D
3->5' Exonuclease activity
Question 3
In prokaryotes during replication, the lagging strand synthesized in a series of short fragments known as Okazaki fragments, consequently requiring many primers. The RNA primers of okazaki fragments are subsequently degraded by DNA polymerase I and the gap once the primer have been removed from lagging strand?
A
DNA polymerase I do not require primer
B
DNA from leading strand serves as primer
C
End of existing Okazaki fragments on lagging strand serves as primer
D
DNA polymerase I has its own primer
Question 4
Genome of Virus is made up of
A
DNA or RNA
B
Proteins
C
DNA
D
RNA
Question 4 Explanation:
The composition & structure of virus genomes (i.e. the nucleic acid which encodes the genetic information of the virus) is more varied than any of those seen in the entire bacterial, plant or animal kingdoms.
Virus genomes range in size from approximately 3,200 nucleotides (nt) (e.g. Hepadnaviruses) to approximately 1.2 million base pairs (Mbp, Mimivirus)
Question 5
Most Plant Viruses Contain
A
Both A and B
B
DNA
C
RNA
D
None of the above
Question 6
DNA which is the sear of all the hereditary characters is chiefly found in...
A
Nucleous
B
Chloroplast
C
None of the above
D
Mitochondria
Question 6 Explanation:
DNA which is seat of all hereditary characters is chiefly found in chromatin in the nucleus where it is associated with the protein called Histones. Some DNA is also found in Mitochondria and Chloroplasts.
Question 7
Who demonstrates that DNA replicates in a semi-conservative manner?
A
McLeod and McCarty
B
Meselson and Stahl
C
Watson and Crick
D
Jacob and Monad
Question 8
Formation of new DNA molecules from the parent DNA which are exactly similar to its replica is called ...
A
Gene mutation
B
Segmentation of DNA
C
Replication of DNA
D
Terminalization of DNA
Question 9
The Two polynucleotide chains of the parent DNA molecule separate due to breaking of
A
H-bond
B
S-bond
C
O-bond
D
All of the above
Question 10
When does a replication of DNA take place?
A
During interphase between two mitotic cycles
B
During mitosis
C
During meiosis
D
During pachytene and diplotene of meiosis
Question 11
Which of the following statement /statements is/are correct regarding replication of DNA?
A
Replication starts at a specific point called origin
B
Replication is a semi-conservative process in which each of the two double helices formed from the parent double strand have one old and one new strand
C
All of the statements are correct
D
Two strands of double helix of DNA unwind with the help of a DNA unwinding protein which binds to single DNA strands.
Question 12
Who demonstrated by auto-radiography that both chromatids during prophase have half old and half new material?
A
McLeod and McCarty
B
Watson and Crick
C
Jacob and Monad
D
Taylor et al
Question 13
Replication may proceed...
A
In only one direction (unidirectional)
B
Can not be determined
C
None of these
D
In both direction (bidirection)
Question 14
Which of the following enzymes are used to join bits of DNA?
A
DNA ligase
B
Endonuclese
C
Primase
D
DNA polymerase
Question 15
Semi conservative replication of DNA was first demonstrated in
A
Streptococcus Pneumonae
B
Escherichia Coli
C
Salmonella typhimuriam
D
Drosophila melanogaster
Question 16
Mode of DNA replication in E.Coli is
A
Conservative and bidirectional
B
semi-conservative and bidirectional
C
semi-conservative and unidirectional
D
Conservative and unidirectional
Question 17
When DNA replication starts
A
The leading strand produces Okazaki fragments
B
The hydrogen bonds between the nucleotides of two strand break
C
The bonds between the nitrogen base and deoxyribose sugar break
D
The phosphodiester bonds between the adjacent nucleotides break
Question 18
During the replication of DNA, the synthesis of DNA on lagging strand takes place in segments, these segments are called
A
Korenbeg segments
B
Double helix segments
C
Okazakii segments
D
Satellite segments
Question 19
The elongation of the leading strand during DNA synthesis
A
Occur in 3'-5' direction
B
Depend on the action of DNA polymerase
C
Produced Okazaki fragment
D
Progresses away from the replication fork
Question 20
Number of hydrogen bonds between G-C bond in DNA
A
Four
B
One
C
Two
D
Three
Question 21
All of the following are features of DNA polymerase complex except
A
can copy long strands of SSDNA
B
Capable of copying 0.5mb of DNA
C
Can proof read and repair in the event of copying error
D
Can polymerize about 100 nucleotides per second
Question 22
Each daughter cell contains DNA molecules with
A
Molecule of parent doubly conserved due to replication
B
Information of parent DNA fully conserved
C
Molecule of parent fully conserved
D
Information of parent DNA semi-conserved
Question 23
Jumping genes are
A
Microsatellite repeats
B
Bacteriophages
C
Transposons
D
Retroposons
Question 24
Which of the following is Cationic
A
Nucleoplasmin
B
All of the given are cationic
C
DNA
D
Histone
Question 24 Explanation:
Histones are basic proteins, which are having basic amino acids Arginine and Lysine in high amount. DNA is anionic because of the presence of Phosphate molecule.
Question 25
Unwinding of DNA is done by
A
Ligase
B
Helicase
C
Topoisomerase
D
Hexonuclease
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